4t^2+2t+1=0

Solution for 4t^2+2t+1=0 equation:

Simplifying
4t2 + 2t + 1 = 0

Reorder the terms:
1 + 2t + 4t2 = 0

Solving
1 + 2t + 4t2 = 0

Solving for variable 't'.

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
0.25 + 0.5t + t2 = 0

Move the constant term to the right:

Add '-0.25' to each side of the equation.
0.25 + 0.5t + -0.25 + t2 = 0 + -0.25

Reorder the terms:
0.25 + -0.25 + 0.5t + t2 = 0 + -0.25

Combine like terms: 0.25 + -0.25 = 0.00
0.00 + 0.5t + t2 = 0 + -0.25
0.5t + t2 = 0 + -0.25

Combine like terms: 0 + -0.25 = -0.25
0.5t + t2 = -0.25

The t term is 0.5t.  Take half its coefficient (0.25).
Square it (0.0625) and add it to both sides.

Add '0.0625' to each side of the equation.
0.5t + 0.0625 + t2 = -0.25 + 0.0625

Reorder the terms:
0.0625 + 0.5t + t2 = -0.25 + 0.0625

Combine like terms: -0.25 + 0.0625 = -0.1875
0.0625 + 0.5t + t2 = -0.1875

Factor a perfect square on the left side:
(t + 0.25)(t + 0.25) = -0.1875

Can't calculate square root of the right side.

The solution to this equation could not be determined.